Light travels 9.45 \cdot 10^{15}9.45⋅10 15 9, point, 45, dot, 10, start superscript, 15, end superscript meters in a year. there are about 3.15 \cdot 10^73.15⋅10 7 3, point, 15, dot, 10, start superscript, 7, end superscript seconds in a year. how far does light travel per second?

We are given that the distance light travel is:

9.45 x 10^15 meters / year

And that there is:

3.15 x 10^7 seconds / year

So the distance light travels per second is:

distance = (9.45 x 10^15 meters / year) * (1 year / 3.15 x 10^7 seconds)

distance = 3 x 10^8 meters / second

  meter per seconds

Step-by-step explanation:

In 1 year the distance traveled by light = meters,

Thus, light travels meter in a second.

⇒ Its speed = meter per seconds

answer: what equations are there

step-by-step explanation:

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it