The sum of three integers is 74. the first integer is twice the second and the third is six more than the second. what are the three integers

Let thw second integer be x
then the first = 2x
and the third integer is = 6+x
their sum = 74
x+2x+6+x = 74
4x +6 = 74
4x = 74-6 =68
x =68÷4
x = 17
then the first integer is 2×17 = 34
the third integer is 17+6 = 23

the integers are 17 , 23 and 34

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