Find the rate of change of the volume of a ball with respect to time when the radius is 10 cm if the radius changes at a constant rate of 2cm/sec (v= 4/3πr^3)

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

idk

step-by-step explanation: