Arectangular field has the perimeter of 772 feet. if the length is 8 feet longer than twice the width, what are the dimensions of the field?

the answer would be c:   ax + b = ax + c

step-by-step explanation:

step-by-step explanation:

for the free

127

whether it's diameter, or radius, i believe if i remember correctly from school, every amount has to always add up to 180. so if you take 53, and starting adding, long story short, taking 127 and adding it to 53, gives you 180.