What is the equation of a circle with a center at (1, 1) and a radius of 5?

Supposing the center of the circle is at (h,k) and that the radius is r, the standard equation for the circle is (x-h)^2 + (y-k)^2 = r^2.

If the center is at (1,1) and the radius of the circle is 5, then

(x-1)^2 + (y-1)^2 = 5^2 (answer)

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!