The formula k=c+273.15k=c+273.15 converts temperatures from celsius cc to kelvin kk. a. solve the formula for cc. c=c= b. convert 300 kelvin to celsius. write your answer using decimals. 300k=300k= ∘c

a. We are given that the formula for Celsius (c) to Kelvin (k) is:

k = c + 273.15

Now to solve for the formula for c, simply subtract 273.15 from both sides, so that:

k – 273.15 = c + 273.15 – 273.15

k – 273.15 = c

Rearranging:

c = k – 273.15

b. We are given that k = 300 Kelvin, therefore find for c:

c = k – 273.15

c = 300 – 273.15

c = 26.85°C

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."