Use δabc shown below to answer the question that follows: triangle abc with segment ad drawn from vertex a and intersecting side cb. which of the following is a step towards proving the similarity of triangles δabc and δdba? segment bc is a hypotenuse. angle b is congruent to itself. segment ba is shorter than segment bc. segment bc is intersected by segment ad.

Given: Triangle ABC with segment AD drawn from vertex A and intersecting side CB.

To Find: First Step towards proving the similarity of triangles ΔABC and ΔDBA.

Solution:  

In ΔABC and ΔDBA

As we can see that to prove that two triangles are similar , their corresponding sides should be proportional and their corresponding interior angles should be equal.

As Ratio of corresponding sides of triangles ΔABC and ΔDBA are not given.

But we can observe from two triangles that

Angle B is common between two  triangles ΔABC and ΔDBA , whatever be the measure of angle B .

So, Option (B): Angle B is congruent to itself is correct option.

d) the triangle is a right triangle 60 squared +144 squared= 156 squared

step-by-step explanation:

156 squared is the hypothenuse

so 156= c