The equation of a parabola is given. y=1/8x^2+4x+20 what are the coordinates of the focus of the parabola?

Convert it to  vertex form we get 

y = 1/8(x + 16)^2 - 12     

so the vertex is at (-16,-12) and  the x coordinate of the focus will be -16)

The focus  will be at (-16, k + p)    Here k = -12 from the vertex equation and  p  = 1 / 4a  where a = 1/8    so p = 1 / 1/2 = 2  So k + p = -12 + 2 = -10

So the coordinates of the focus are (-16, -10) answer

Arhombus is a quadrilateral.

The first option would be correct if it were one half and not one