Rotating a polygon in quadrant ii 270° clockwise is the same as a) rotating it 90° clockwise. b) rotating it 180° clockwise. c) rotating it 90° counterclockwise. d) rotating it 270° counterclockwise.

90°

Step-by-step explanation:

Hi! A and B are definitely not the right answers, because that’s basically rotating it forward even more. Rotating a polygon in Quadrant II 370 degrees clockwise is like rotating it 99 degrees counterclockwise, because the next 90 degrees you were to rotate it, it would be in it’s original position. The answer is C.

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: