The magnitude, m, of an earthquake is defined to be m=log i/s, where i is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and s is the intensity of a “standard” earthquake, which is barely detectable. what is the magnitude of an earthquake that is 35 times more intense than a standard earthquake? use a calculator. round your answer to the nearest tenth.

log(35) = 1.544

 rounded to nearest tenth = 1.5

The magnitude of the earthquake that is 35 times more intense than a standard earthquake=1.5

Step-by-step explanation:

Given : The magnitude M of an earthquake is defined to be  ---(1)

, where I is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and

S is the intensity of a “standard” earthquake, which is barely detectable.

If  the magnitude of an earthquake that is 35 times more intense than a standard earthquake

⇒Intensity of earthquake I=35 S

Substitute the value of I in (1), we get

∴ The magnitude of the earthquake that is 35 times more intense than a standard earthquake=1.5

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