The pair of points is on the graph of an inverse variation. find the missing value. (2.4, 3) and (5, y) 1.44 6.25 0.69 1

Hence, the value of y is:

1.44

Step-by-step explanation:

It is given that:

The pair of points is on the graph of an inverse variation.

(2.4, 3) and (5, y)

We have to find the missing value y in the point.

As we know that in the inverse variation the value of y is the inverse value of x by some k.

i.e. in first point (2.4,3) let 'k' be a number such that:

Hence, the inverse is k=7.2

Now in the second point (5,y) we find the value of y as:

Hence, the value of y is:

1.44

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

27 +27 or 27times 2=54

the diffrence is 0