Wyatt’s eye-level height is 120 ft above sea level, and shawn’s eye-level height is 270 ft above sea level. how much farther can shawn see to the horizon? use the formula mc024-1.jpg, mc024-2.jpg with d being the distance they can see in miles and h being their eye-level height in feet.

The formula is:

d = √ [ 3h / 2], for h > 0

where d is the distance they can see in miles, and h is their eye-level height in feet.

In the case of Wyatt, h = 120 ft

=> d = √ [ 3(120) ] / 2 = √180 = 13.42 miles

In the case of Shawn, h = 270 ft

=> d = √ [ 3 (270) / 2 ] = √ 405 = 20.12 miles

Given that the question is how much farther Shawn can see to the horizon, you must find the difference:

20.12 miles - 13.42 miles = 6.7 miles

6.7 miles

Letter b hope it