3questions math! ! add using a number line. 56+(−116) drag and drop the word sum to the correct value on the number line. add 34+(−212) using the number line. select the location on the number line to plot the sum. what is the sum? 1.3+(−2.4) enter your answer, as a decimal, in the box.

Steps of adding 56+(−116) using number line are as following:

1) Draw a number line by ranging from -120 to +60.

2) Point out 56 on the number line.

3) Because -116 is added to 56 on the number line,  please move 116 numbers left to 56 on the number line. We always go left in addition of a negative number on the number line.

4) The number we reach -60 on left side would be our final sum.

b) Steps of adding 34+(−212) using number line are as following:

1) Draw a number line by ranging from -212 to +40.

2) Point out 34 on the number line.

3) Because -212 is added to 34 on the number line,  please move 212 numbers left to 34 on the number line. We always go left in addition of a negative number on the number line.

4) The number we reach -178 on left side would be our final sum.

c) Steps of adding 1.3+(-2.4) using number line are as following:

1) Draw a number line by ranging from -3 to +3.

2) Point out 1.3 on the number line.

3) Because -2.4 is added to 1.3 on the number line,  please move 2.4 numbers left to 1.3 on the number line. We always go left in addition of a negative number on the number line.

4) The number we reach -1.1 on left side would be our final sum.

4

Step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2