Which equation could be used to solve this problem? the sum of two consecutive odd integers is 100. find the integers. a.2n + 3 = 100 b.2n + 1 = 100 c. n + 4 = 100 d.2n + 2 = 100

An even integer is represented as 2n where n is an integer. an odd integer is represented as 2n+1
all even numbers are 2 away from the next even number

all odd numers are 2 away from the next odd number so

the sum of 2 consecutive odd intergesrs s 100

consecutive odd=(2n+1)+(2n+1+2) and so on

so consecutive odd =100 so
2n+1+2n+1+2=100

4n+4=100

the closest equation is

the equation is 4n+4

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