Mathematics, 03.07.2019 18:40 marissalwilliams3
The radius of a dr. pepper can is 3 cm and the height is 12 cm. what is the distance from the center of the bottom of the can to the edge of the top of the can?
Answers: 1
Mathematics, 21.06.2019 21:30
In δabc shown below, â bac is congruent to â bca: triangle abc, where angles a and c are congruent given: base â bac and â acb are congruent. prove: δabc is an isosceles triangle. when completed (fill in the blanks), the following paragraph proves that line segment ab is congruent to line segment bc making δabc an isosceles triangle. (4 points) construct a perpendicular bisector from point b to line segment ac . label the point of intersection between this perpendicular bisector and line segment ac as point d: mâ bda and mâ bdc is 90° by the definition of a perpendicular bisector. â bda is congruent to â bdc by the definition of congruent angles. line segment ad is congruent to line segment dc by by the definition of a perpendicular bisector. δbad is congruent to δbcd by the line segment ab is congruent to line segment bc because consequently, δabc is isosceles by definition of an isosceles triangle. 1. corresponding parts of congruent triangles are congruent (cpctc) 2. the definition of a perpendicular bisector 1. the definition of a perpendicular bisector 2. the definition of congruent angles 1. the definition of congruent angles 2. the definition of a perpendicular bisector 1. angle-side-angle (asa) postulate 2. corresponding parts of congruent triangles are congruent (cpctc)
Answers: 1
Mathematics, 21.06.2019 22:00
Solve 2 - 3 cos x = 5 + 3 cos x for 0° ⤠x ⤠180° a. 150° b. 30° c. 60° d. 120°
Answers: 1
Mathematics, 22.06.2019 00:00
What is the value of x in this triangle? a. 53° b. 62° c. 65° d. 118°
Answers: 2
Mathematics, 22.06.2019 00:20
Find the power set of each of these sets, where a and b are distinct elements. a) {a} b) {a, b} c) {1, 2, 3, 4} show steps
Answers: 1
The radius of a dr. pepper can is 3 cm and the height is 12 cm. what is the distance from the center...
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