The perimeter of a square is 20 ft. if you increase the length of the square by 2 feet and decrease the width by 1 foot what is the area, in square feet, of the new figure?

A square has four equal sides a, so the perimeter is 4a.

The side of the square is 5 ft long.

The length is increased by 2 ft -> 5+2=7 ft.
The width is decreased by 1 ft -> 5-1=4 ft.

The new figure is a rectangle with the dimensions 4 ft x 7 ft.
The area of a rectangle is the product of the length and the width.


The area of the new figure is 28 ft².

The answer is a good luck