Mathematics, 25.09.2019 17:30 cuhh
What is the rate of change for f(x) =7 sin x-1 on the interval from x=0 to x=piover 2
Answers: 1
![\bf f(x)= 7sin(x)-1 \qquad \begin{cases} x_1=0\\ x_2=\frac{\pi }{2} \end{cases}\implies \cfrac{f\left( \frac{\pi }{2} \right)-f(0)}{\frac{\pi }{2}-0} \\\\\\ \cfrac{[7\cdot 1-1]~-~[7\cdot 0-1]}{\frac{\pi }{2}}\implies \cfrac{6-(-1)}{\frac{\pi }{2}}\implies \cfrac{6+1}{\frac{\pi }{2}}\implies \cfrac{7}{\frac{\pi }{2}}\implies \cfrac{14}{\pi }](/tpl/images/0261/9491/a2931.png)
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What is the rate of change for f(x) =7 sin x-1 on the interval from x=0 to x=piover 2...
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