Two friends, bob and ben, each buy one lottery ticket. each ticket contains six numbers from a total of one hundred numbers (0–99). bob chooses the numbers 1, 2, 3, 4, 5, 6, and ben chooses the numbers 39, 45, 66, 72, 74, 89. who has a higher probability of winning?

 Bob and Ben, both have equal probabilities of winning.

Step-by-step explanation:  Given that Bob and Ben are two friends who buy one lottery ticket each. Each ticket contains six numbers from a total of one hundred numbers from 0 to 99.

Bob chooses the numbers 1, 2, 3, 4, 5, 6, and Ben chooses the numbers 39, 45, 66, 72, 74, 89.

We are to select the friend who has a higher probability of winning.

Let, 'S' be the sample space for the experiment.

Then, S = {0, 1, 2, . . . , 98, 99}      ⇒  n(S) = 100.

Let, B and F are the events that Bob win and Ben win respectively.

Then,

B = {1, 2, 3, 4, 5, 6}     ⇒  n(B) = 6

and

F = {39, 45, 66, 72, 74, 89}     ⇒  n(F) = 6.

Therefore, the probability of even t B is

and the probability of event F is

Since, both the events have equal probabilities, so there is an equal chance of winning of Bob and Ben.

Thus, both the friends have equal probabilities of winning.

let x be the money she spent so that she can earn the free t-shirt.

since, she already spent $112.49

⇒

also, as per the statement: jennifer must spend $250 or more in order to qualify for a free t-shirt at the store.

then,

we have an inequality i.,e

subtract 112.49 from both sides we get;

therefore, $137. 51 more money does jennifer need to spend so that she can earn the free t-shirt