Mathematics, 01.07.2019 20:00 cay88

The normal body temperature of a camel is 37 degrees celsius the temperature varies by up to three degrees c throughout the day. write and solve an absolute value inequality that represents the range of normal body temperatures in degrees celsius of a camera throughout the day where to represents the normal body temperature?

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The normal body temperature : to = 37° C
An inequality is:
| t - to | ≤ 3
| t - 37 | ≤ 3
t - 37 ≤ 3     AND ( - t - 37 ) ≤ 3
t ≤ 3 + 37               - t + 37 ≤ 3
t ≤ 40                     - t ≤ 3 - 37
                              - t ≤ - 34   / * ( - 1 )
                                t ≥ 34
Answer t ∈ [ 34°C, 40° C ].

Answer from: chloejason8375

The range of normal body temperatures in degrees celsius of a camel throughout the day when $t\in[34^\circ \rm{C},\; 40^\circ \rm{C}]$ .

Explanation:

Given: The normal body temperature of a camel is degrees celsius the temperature varies by up to three degrees celsius throughout the day.

Let the normal temperature of camel be $t_{o}$ .

According to the question,

Absolute temperature of camel's body throughout day is calculated as

$\\\vert {t-t_{o}} \rvert}\leq3\\\\\vert {t-37} \rvert}\leq3\\$

Now, solving the inequality:

$(t-37)\leq3$ and $-(t-37)\leq3$

$t-37+37 \leq {37+3}$ and ${-t+37}\leq3$

$t\leq40$ $-t+37-37\leq3-37$

$-t\leq-34\\$

${t\geq34}$

Here, range of temperature is $[34^\circ \rm{C},\; 40^\circ \rm{C}]$

Therefore, the range of normal body temperatures in degrees celsius of a camel throughout the day when $t\in[34^\circ \rm{C},\; 40^\circ \rm{C}]$ .

Learn more about linear inequality here:

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Answer from: Quest

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Answer from: Quest

Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )
Ineed as soon as possible ! what is the approximate length of the minor arc de

Ineed as soon as possible ! what is the approximate length of the minor arc de

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