Point c ∈ ab , ab = 18 cm. the distance from c to a is 3 cm shorter than the distance to b. find ac and cb.

The measure of AC and CB are 7.5 and 10.5 respectively

The distance between two points on a graph is known as a line.

If C is on a point AB, then;

AC +CB = AB 1

If the distance from C to A is 3 cm shorter than the distance to B, then:

AC = CB - 3 2

Substitute equation 2 into 1 to have;

AC +CB = AB

CB - 3 +CB = AB

2CB - 3 = 18

2CB = 18 + 3

2CB = 21

CB = 21/2

CB = 10.5

Recall that AC = CB - 3

AC = 10.5 - 3

AC = 7.5

Hence the measure of AC and CB are 7.5 and 10.5 respectively

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AC = 7.5 cm

CB=10.5 Cm

Step-by-step explanation:

Given that point  C in between point A and B

AB= 18 cm

lets distance between CA = x

then  distance between CB will be =x +3

Also give that AB =18 cm

So by adding CA and AB

x + x +3 =18

2 x =15

So x=7.5 cm

So

AC = 7.5 cm

CB=10.5 Cm

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

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step-by-step explanation: