An equation is shown below:
4(2x β 5) = 4
part a: how many solutions does this equatio...
Mathematics, 16.09.2019 20:00 sierravick123owr441
An equation is shown below:
4(2x β 5) = 4
part a: how many solutions does this equation have? (4 points)
part b: what are the solutions to this equation? show your work. (6 points)
Answers: 2
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X+ 4y β z = β14 5x + 6y + 3z = 4 β2x + 7y + 2z = β17
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