Find (d^2)y/d(x^2) in terms of x and y of (x^2)(y^2) - 6 x = 6 using implicit differentiation (2(x^2)(y^4)-3x(y^2)-3)/((x^4)(y^3) is not the right answer and i'm not sure y.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72