Given the equations x = 6y, 4y = 9z, and (3x)(9z) = ky, what is the value of k in terms of y, if y ≠ 0?

72y

Step-by-step explanation:

To find the value of 3x in terms of y, multiply both sides of the equation x = 6y by 3: 3x = 18y. Also, since 4y = 9z, by the Commutative Property, 9z = 4y. Therefore, by substitution, (18y)(4y) = ky, or 72y22 = ky, and if both sides of the equation are divided by y, the value of k is shown to be 72y.

third option: 6x+8

step-by-step explanation:

we can see that the given question is a sum of series and the values of n vary from 0 to 3

the first term will be:

when n=0, [(0)*x+2] => (0+2) => 2

when n=1, [(1)*x+2] => (x+2) => x+2

when n=2, [(2)*x+2] => 2x+2

when n=4, [(3)*x+2] => 3x+2

so adding up all the terms will give us:

=2+x+2+2x+2+3x+2

=x+2x+3x+2+2+2+2

=6x+8

so,

third option is the correct answer ..

can you rephrase the question ? it is unclear : -)

step-by-step explanation: