The amount a string stretches varies linearly with the mass applied to the spring, as can be seen in the video. in the video, with no additional mass, the hanger was 30.6 cm off the ground. with 150 grams of additional mass, the hanger was 16.2 cm off the ground. a wooden block stretched the spring so the hanger was 24.8 cm off the ground. determine the mass of the wooden block, to at least 1 decimal place.

The mass of the wooden block is 60.4 grams.

Step-by-step explanation:

Since we have given that

Without any additional mass , the hanger was 30.6 cm off the ground.

Let the function will be

f(m)=km, where k is a constant.

With 150 grams of additional mass, the hanger was 16.2 cm off the ground.

So, our function becomes,

Now, our function becomes,

Now, the wooden block stretched the spring so, the hanger was 24.8 cm off the ground.

The mass of the wooden block is given by

Hence, the mass of the wooden block is 60.4 grams.

45

step-by-step explanation:

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3