From a committee of 6 girls and 4 boys, a name is selected. then another name is selected. what is the probability that both people drawn will be girls?

First draw is 6 out of 10  = 6/10 = 3/5
Second draw is 5 girls out of 9 remaining children  = 5/9

Now we multiply the probabilities:

3/5  x 5/9   (you can cancel out the 5's since one is in the numerator and the other is in the denominator.  You can also reduce the 3 and 9.  The answer is 3/9=1/3
So the chances that the first two selected will be girls is 1/3.