A29% dextrous solution (29mg per 100ml of solution) is given intravenously. suppose a total of 3.99l of the solution is given over a 14-hour period. complete parts (a) through (c) below. a. what is the flow rate in units of ml/hr? ml/hr (type an integer or decimal rounded to the nearest thousandth as needed.) what is the flow rate in dextrous per hour? mg/hr (type an integer or decimal rounded to the nearest thousandth as needed.) b. if each ml contains 12 drops (the drop factor is expressed as 12 ggt/ml), what is the flow rate in units of ggt/hr? ggt/hr (type an integer or decimal rounded to the nearest thousandth as needed.) c. during the 14-hour period, how much dextrous is delivered? mg (type an integer or decimal rounded to the nearest thousandth as needed.)

(a) The flow rate is 285 mL/hr  and the flow rate in dexterous per hour is 82.65.

(b) The flow rate in units of ggt/hr is 3420.

(c) 1157.1 mg

Step-by-step explanation:

It is given that a 29% dexterous solution (29mg per 100mL of solution) is given intravenously.

A total of 3.99L of the solution is given over a 14-hour period.

(a)

We know that 1 L = 1000 mL.

The flow rate in units of mL/hr is

Therefore, the flow rate is 285 mL/hr .

The flow rate in dexterous per hour is

The flow rate in dexterous per hour is 82.65.

(b)

It is given that each mL contains 12 drops (the drop factor is expressed as 12 ggt/mL).

The flow rate in units of ggt/hr is

Rate in units of ggt/hr = Flow rate in mL/hr × Drop factor 12 ggt/mL

Therefore, the flow rate in units of ggt/hr is 3420.

(c)

It is given that a total of 3990 mL of the solution is given over a 14-hour period.

The amount of dexterous delivered during the 14-hour period is 29% of 3990.

Therefore, 1157.1 mg is of dexterous delivered during the 14-hour period.

$649.60

step-by-step explanation:

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt