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Mathematics, 01.07.2019 03:00 Jamalmcc8nh78

By first differentiating (√(1-x))/(√(1+x)) obtain an expression dy/dx in terms of x. hence show that the gradient of the normal to the curve at point (x, y) is (1+x)(√(1-x^2))

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By first differentiating (√(1-x))/(√(1+x)) obtain an expression dy/dx in terms of x. hence show that...
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