In a large biology class, the scores of the final exam were approximately normally distributed with the mean 80.5 and standard deviation 9.9. what proportion of final exam scores were greater than 68.3

The standardized z score is  68.3 - 80.5
                                             =    -1.263
                                                 9.9 

Referring to the Standard Normal Curve tables 
proportion greater than 68.3 =  1 - 0.3966 = 0.603 

or 60.3%

X=y+4 is the answe