How many solutions does the equation have? 6h−(9−3h)=6−3(h+2)

Find the indicated value, where g(t) = t^2-t and f(x)= 1+x a. -2 b. 0 c. 2 d. 8

Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tau∫0tv(τ) dτ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equals≤tless than or equals≤startfraction pi over 3 endfraction π 3.

Need so much on this one how many yards?