The table below shows data from a survey about the amount of time students spend doing homework each week. The students were in either college or high school:HighLowQ1Q3IQRMedianMeanσCol lege206818101413.35.2High School2035.51610.511115.4Which of the choices below best describes how to measure the spread of these data?(Hint: Use the minimum and maximum values to check for outliers.) Both spreads are best described by the IQR. Both spreads are best described by the standard deviation. The college spread is best described by the IQR. The high school spread is best described by the standard deviation. The college spread is best described by the standard deviation. The high school spread is best described by the IQR. Can you please help me understand how to solve this problem?

Firstly, let us check for the outliers as instructed in the question

For college,

Q3 = 18

Q1=8

IQR = 10

maximum = 20

minimum = 6

For there to be outliers, The maximum must be greater than Q3 + 1.5(IQR) or the minimum must be less than Q1 -1.5(IQR)

Q3 + 1.5(IQR) = 8 + 1.5(10) = 23

Q1 -1.5(IQR) = 6 - 1.5(10) = -9

The maximum (20) is not greater than 23 and the minimum (6) is not less than -9. Hence we can conclude that college data has no outlier

For High school,

Q3 = 16

Q1= 5.5

IQR = 10.5

maximum = 20

minimum = 3

Q3 + 1.5(IQR) = 16 + 1.5(10.5) = 31.75

Q1 -1.5(IQR) = 5.5 - 1.5(10.5) = -10.25

The maximum (20) is not greater than 31.75 and the minimum (3) is not less than -10.25. Hence we can conclude that High school data has no outlier

Since both spreads have no outliers, The best way to describe the spreads is by their IQR.

The makes the correct answer to be the first option that is (Both spreads are described by their IQR)

2 & 7

step-by-step explanation:

he climbs 300 ft/hr at a constant rate. the peak is at 1,500 ft.

when going up, he reaches 600 ft in 2 hours. remember, that he is going in a constant rate. divide 600 with 300:

600/300 = 2

assuming that he takes the same route back (meaning that it's a 1500 ft route back, you can solve.

note also that you are solving when he gets back to 600 ft after he reaches the peak.

first, find the amount of hours it takes to get up the peak. divide the total amount (1500), with the ft/her (300) to get the amount of hours (x):

1500/300 = x

x = 5

it takes jamie 5 hours to get up. now, he is returning down, and reaches 600 (his current destination). remember that he climbs at a constant 300 ft/hr. divide 600 with 300:

600/300 = x

x = 2

now add the two numbers together.

x = 5 + 2 = 7

jamie takes 7 hours to go up the mountain and reach his current position when descending.

(total amount/constant rate) = (time).

remember that it is a constant rate, so in total, when he gets back down the mountain, it will take the same amount of time as when he goes up. the total amount for the round trip is: 5 + 5 = 10.

~

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).