A coordinate grid with 2 lines. One line, labeled f(x) passing through (negative 4, 3), the point (negative 2, 1) and (0, negative 1). The other line is labeled g(x) and passes through (negative 4, negative 1), the point (negative 2, 1) and (0, 3). Which input value produces the same output value for the two functions on the graph? x = −3 x = −2 x = −1 x = 3 Mark this and return

it's both, now can you answer my most recent question?

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

10010010001010010101001001010010100101010010101010010010101010110010001011010010010001

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.