Assume that x and y are both differentiable functions of t and find the required values of dy/dt and dx/dt. y = √x
(a) Find dy/dt, given x = 1 and dx/dt = 9.
dy/dt =
(b) Find dx/dt, given x = 49 and dy/dt = 2.
dx/dt =

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

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step-by-step explanation:

just get this app called photo math it should be able to do those

where is the graph? need more info