You measure the lifetime of a random sample of 25 rats that are exposed to 10Sv of radiation (the equivalent of 1000 REM) for with the LD100 is 14 days. The sample mean is x=13.8 days. Suppose that the lifetimes for this level of exposure follow a normal distribution with unknown mean and standard deviation 0.75. you read a report that says "on the basis of random sample of 25 rats, a confidence interval for the true mean survival time extends from 13.45 to 14.15 days." The confidence level for this interval is?

answer: you need to organize this better it does not make sense.

step-by-step explanation: ?

2 apples

step-by-step explanation:

taking away equals subtraction. 6-4=2

the value of x is 9 ⇒ answer b

step-by-step explanation:

* we can solve this problem using cosine and sine rule

- in δ abc

∵ ab = 36 , bc = 28 , ac = 16

- lets find the measure of angle b using the cosine rule

∵ cos b = [ab² + bc² - ac²]/2(ab)(bc)

∴ cos b = [36² + 28² - 16²]/2(36)(28)

∴ cos b = 19/21

∴ m∠b = cos^-1(19/21) ≅ 25°

- lets find the measure of angle a using the sine rule

∵ sina/bc = sinb/ac = sinc/ab

∴ sina/28 = sin25°/16 ⇒ by using cross multiplication

∴ sina = 28 × sin25°/16

∴ sina = 0.7396

∴ m∠a = sin^-1(0.7396) ≅ 48°

- from the figure m∠abd = m∠dbc

∵ m∠abc = 25°

∴ m∠abd = 25°/2 = 12.5°

- in δabd

∵ m∠a = 48° , m∠abd = 12.5°

∵ the sum of the measures of the interior angles of any δ is 180°

∴ m∠adb = 180° - (48° + 12.5°) = 119.5°

∵ ab = 36

∵ ad = x

- use the sine rule to find x

∵ sin∠adb/ab = sin∠abd/x

∴ sin119.5°/36 = sin12.5°/x ⇒ by using cross multiplication

∴ x = 36 × sin12.5°/sin119.5° = 8.95 ≅ 9

* the value of x is 9

answer: you will have more water.