We want to find the zeros of this polynomial:
p(x) = (x+2) (2x^2 + 3x-9)

x = - 2, x = - 3, x =

Step-by-step explanation:

to find the zeros equate p(x) to zero , then

(x + 2)(2x² + 3x - 9) = 0 ← factor the quadratic

(x + 2)(x + 3)(2x - 3) = 0

equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

x + 3 = 0 ⇒ x = - 3

2x - 3 = 0 ⇒ 2x = 3 ⇒ x =

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.