A particle travels along a straight line from a point A on the line. Its velocity after t seconds is (48-3t)cm/s. If its distance from A after t seconds is s cm, find s in terms of t. Hence find the time that elapses before the particle is back again at A.

16 s

Step-by-step explanation:

Given:

Substituting values into SUVAT formula to find s in terms of t:

To find the time that elapses before the particle is back at A, set s to zero and solve for t:

Therefore, t = 0 and t = 16, so the time that elapses before the particle is back again at A is 16 s

the answer is 62

7/2

(decimal: 3.5)

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step-by-step explanation: