Mathematics, 24.03.2022 04:00 2020kaylahernan
Namrata participates on average in 38 client meetings per month with a standard deviation of 8.2 meetings. Suppose
Namrata's number of client meetings per month are normally distributed. Let X = the number of client meetings in a
particular month. Then X - N(38, 8.2).
If necessary, round to three decimal places
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Namrata participates on average in 38 client meetings per month with a standard deviation of 8.2 mee...
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