Mathematics, 18.03.2022 14:00 jrfranckowiak
[IMAGE INCLUDED] The solution to dy/dx = 2e^(2x+y) with initial condition (0, –ln 5) can be expressed as y = –ln(j – ke^2x) for real numbers j and k. What are the values of j and k?
Answers: 2
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[IMAGE INCLUDED] The solution to dy/dx = 2e^(2x+y) with initial condition (0, –ln 5) can be expresse...
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