Find the zeros of the function g(x) = 3x^2 + 42

There are no zeroes.

Step-by-step explanation:

If you look at the y intercept. It is 42. Furthermore, since there is an asymptote under that, the function is always increasing. Thus, there are no zeroes.

ok

step-by-step explanation:

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: