Based on the quadratic function shows in the table below, what are the coordinates of the vertex of this function? X: Y:



-1 | -14

0 | -8

1 | -6

2 | -8

3 | -14

1) (0,8)
2) (-6,1)
3) (1,-6)
4) (0,2)

Does the function satisfy the hypotheses of the mean value theorem on the given interval? f(x) = 4x^2 + 3x + 4, [−1, 1] no, f is continuous on [−1, 1] but not differentiable on (−1, 1). no, f is not continuous on [−1, 1]. yes, f is continuous on [−1, 1] and differentiable on (−1, 1) since polynomials are continuous and differentiable on . there is not enough information to verify if this function satisfies the mean value theorem. yes, it does not matter if f is continuous or differentiable; every function satisfies the mean value theorem.