The weight W of a steel ball bearing varies directly with the cube of the bearing's radius r according to the formula W= 4/3 pi(p)(r)^3, where p is the density of the steel. The surface area of a bearing varies directly as the square of its radius because A = 4 pi(r^2) a. Express the weight W of a bearing in terms of its surface area

b. Express the bearing's surface area A in terms of its weight.

c. For steel, p = 7.85 g/cm^3. What s the surface area of a bearing weighing 0.62 g?

what statement? is there an image?

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

a

step-by-step explanation: