A spinner has two equal sections, one green and one orange. The spinner is spun three times, resulting in the sample space S = {GGG, GGO, GOG, OGG, GOO, OGO, OOG, OOO}. If the random variable X represents the number of times orange, O, is spun, which graph represents the probability distribution? A probability distribution is shown. The probability of 0 is 1; 1 is 3; 2 is 3; 3 is 1. A probability distribution is shown. The probability of 0 is 0. 13; 1 is 0. 38; 2 is 0. 38; 3 is 0. 12. A probability distribution is shown. The probability of 0 is 0. 12; 1 is 0. 25; 2 is 0. 5; 3 is 0. 12. A probability distribution is shown. The probability of 0 is 0. 12; 1 is 0. 5; 2 is 0. 25; 3 is 0. 12.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

6/20

step-by-step explanation:

ummm seems that u didnt post the attachement !

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.