write an equation of a line passing through the point (-4,11) and perpendicular to the line 4x + 5y = -45

y = 5/4x - 6

Step-by-step explanation:

First, put 4x + 5y= -45 in y = mx + b form

4x + 5y= -45

5y = -4x - 45

y = -4/5x - 9

So, the slope is -4/5. Perpendicular lines have a opposite reciprocal slope, so the line's slope will be 5/4 right so to find the equation of the perpendicular line in this question, plug in the slope and given point into y = mx + b, and solve for b

y = mx + b

-11 = 5/4(-4) + b

-11 = -5 + b

-6 = b

so you should Plug in b and the slope into y = mx + b

y = 5/4x - 6

So, the equation is y = 5/4x - 6

if this doesn't make sense i don't know what will

step-by-step explanation:

let

we know that

the y-intercept is the y-coordinate of the point when the value of x is equal to zero

so

the y-coordinate of the point a is the y-intercept

the answer part a) is

the value of y-intercept is

part b) find the slope m

we know that

the value of the slope is equal to

substitute the values

therefore

the answer part b) is

the value of the slope is equal to

the general answer is

the slope is

the value of y-intercept is