Michaela is making memory boxes. She wants to cover the boxes with sheets of decorative paper on all sides before filling them. This net represents a single memory box. How much paper is needed to cover each memory box?

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in²
Net of rectangular prism. The top rectangle has a horizontal length of 35 inches. There is a second rectangle below it. One either side of the second rectangle, there is a rectangle with a horizontal length of 24 inches and a vertical length of 30 inches. There are two rectangles below the second rectangle.

area = 5220 in²

Step-by-step explanation:

It's a little difficult to ensure accuracy without a diagram of the net, but from what you have said, the net appears to comprise of:

2 rectangles: 35 x 242 rectangles: 24 x 302 rectangles: 35 x 30

Therefore, the total area of the net is:

⇒ area = 2(35 x 24) + 2(24 x 30) + 2(35 x 30)

⇒ area = 5220 in²

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12

Xis equal to three