![2sin(\theta )+\sqrt{3}=0\implies 2sin(\theta )=-\sqrt{3}\implies sin(\theta )=-\cfrac{\sqrt{3}}{2} \\\\\\ sin^{-1}\left[ sin(\theta ) \right]=sin^{-1}\left( -\cfrac{\sqrt{3}}{2} \right) \implies \theta =sin^{-1}\left( -\cfrac{\sqrt{3}}{2} \right)\implies \theta \begin{cases} \stackrel{III~Quadrant}{\frac{4\pi }{3}}\\\\ \stackrel{IV~Quadrant}{\frac{5\pi }{3}} \end{cases}](/tpl/images/2667/2337/7e6a6.png)
If 2sin theta = √3, (0° < theta <90° ), then find the value of theta
...
Mathematics, 22.02.2022 14:00 alejandr1872913
If 2sin theta = √3, (0° < theta <90° ), then find the value of theta
Answers: 1
Another question on Mathematics
Mathematics, 21.06.2019 17:00
When you are making a circle graph by hand, how do you convert a number for a part into its corresponding angle measure in the circle graph? when you are making a circle graph by hand, what should you do if one of your angle measures is greater than 180°?
Answers: 2
Mathematics, 21.06.2019 19:00
The reflexive property of congruence lets you say that ∠pqr ≅
Answers: 1
Mathematics, 21.06.2019 19:30
Given a: b and b: c, find a: b: c. write the ratio in simplest form. a: b=6: 10 and b: c=21: 33
Answers: 1
You know the right answer?
Questions
Computers and Technology, 06.12.2019 04:31
