8. A study found that 72% (0.72) of people wear their seat belts? If three people are selected at random, what is the probability that all three people wear their
seat belts?

0.373248

Step-by-step explanation:

P(A and B) = P(A) * P(B)

Let's say one person wearing a seat belt is event A, the second person wearing a seat belt is event B, and the third person wearing their seat belt is event C

P(A and B and C) = P((A and B) and C) = (P(A) * P(B)) *P(C) = P(A) * P(B) * P(C)

The probability of each is 0.72. Our answer is therefore 0.72 * 0.72 * 0.72, or 0.72³ = 0.373248

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: