Mathematics, 20.02.2022 23:10 allisonklinger1786
Let U = {b, f, k, m, p, r, u, y} A = {b, u, y) Find A. - Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. A'= 4 { } (Use a comma to separate answers as needed.)
Answers: 2
Mathematics, 21.06.2019 19:00
Write the expression in complete factored form. 5n_(c - 3) - n(c - 3) =
Answers: 2
Mathematics, 21.06.2019 20:00
True or false: the graph of y=f(bx) is a horizontal compression of the graph y=f(x) if b< 1
Answers: 2
Mathematics, 21.06.2019 21:30
In δabc shown below, ∠bac is congruent to ∠bca: triangle abc, where angles a and c are congruent given: base ∠bac and ∠acb are congruent. prove: δabc is an isosceles triangle. when completed (fill in the blanks), the following paragraph proves that line segment ab is congruent to line segment bc making δabc an isosceles triangle. (4 points) construct a perpendicular bisector from point b to line segment ac . label the point of intersection between this perpendicular bisector and line segment ac as point d: m∠bda and m∠bdc is 90° by the definition of a perpendicular bisector. ∠bda is congruent to ∠bdc by the definition of congruent angles. line segment ad is congruent to line segment dc by by the definition of a perpendicular bisector. δbad is congruent to δbcd by the line segment ab is congruent to line segment bc because consequently, δabc is isosceles by definition of an isosceles triangle. 1. corresponding parts of congruent triangles are congruent (cpctc) 2. the definition of a perpendicular bisector 1. the definition of a perpendicular bisector 2. the definition of congruent angles 1. the definition of congruent angles 2. the definition of a perpendicular bisector 1. angle-side-angle (asa) postulate 2. corresponding parts of congruent triangles are congruent (cpctc)
Answers: 1
Mathematics, 21.06.2019 23:00
Qrst is a parallelogram. determine the measure of ∠q pls
Answers: 2
Let U = {b, f, k, m, p, r, u, y} A = {b, u, y) Find A. - Select the correct choice below and, if nec...
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