The vertex of a parabola is at (6,5), and its axis of symmetry is vertical. One of the x-intercepts is at (8, 0). What is the x-coordinate of the other x-intercept?

Step-by-step explanation:

Vertex form of the quadratic equation:

where the vertex is

Given vertex = (6, 5):

If one the x-intercepts is (8, 0):

Therefore, equation of parabola:

x-intercepts occur when f(x) = 0:

Therefore, the x-coordinate of the other x-intercept is 4.

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.

thats not a system of equations, that is a solution