A quarterback throws an incomplete pass. The height of the football at time t is modeled by the equation h(t) = –16t2 40t 7. Rounded to the nearest tenth, the solutions to the equation when h(t) = 0 feet are –0. 2 s and 2. 7 s. Which solution can be eliminated and why? The solution –0. 2 s can be eliminated because time cannot be a negative value. The solution –0. 2 s can be eliminated because the pass was not thrown backward. The solution 2. 7 s can be eliminated because the pass was thrown backward. The solution 2. 7 s can be eliminated because a ball cannot be in the air for that long due to gravity.

i dont know sorry

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

hm let me think hm think think hm think yes