There are 4 aces and 4 kings in a standard deck of playing cards. you pick one random card at random. What is the probability of selecting an ace or king? Note: It has to be a fractaion

2/3

Step-by-step explanation:There are 52 cards in a standard deck: 13 ordinal cards (Ace - 10, Jack, Queen, King) and 4 of them - one to each suit (hearts, diamonds, clubs, spades) and so we have

4

×

13

=

52

.

There are 8 cards that fit the question (4 each of aces and kings).

And so in a random draw, the odds of drawing one of those 8 cards out of the total number of 52 is:8/52

which we can simplify:

8/52=2/13

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

correct answer:

b.(19,-2)