Don cheTD invested $ 6,300 in Account in the year 20066, Its been reached $8,200 in 2010
Determine the value of the account in 2019

y = abᵗ

we know the initial amount is 6300 on 2006, that's on year 0, namely t = 0.

we also know that it became 8200 on 2010, that's 4 years later, namely t = 4.

what would its value be in 2019, well that's t = 13.

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680

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step-by-step explanation:

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